document.write( "Question 590625: I don't really understand this problem, it would be appreciated if you can show the steps and how to get the answer. thanks!\r
\n" ); document.write( "\n" ); document.write( "If the perimeter of a rectangle is 104 inches and the length of the rectangle is 6 inches less than its width, find the area of the rectangle.
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Algebra.Com's Answer #375300 by ankor@dixie-net.com(22740)\"\" \"About 
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If the perimeter of a rectangle is 104 inches and the length of the rectangle is 6 inches less than its width,
\n" ); document.write( " find the area of the rectangle.
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\n" ); document.write( "The perimeter equation
\n" ); document.write( "2L + 2W = 104
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\n" ); document.write( "It says,\" the length of the rectangle is 6 inches less than its width,\", therefore:
\n" ); document.write( "L = W - 6
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\n" ); document.write( "In the perimeter equation, replace L with (W-6)
\n" ); document.write( "2(W-6) + 2W = 104
\n" ); document.write( "2W - 12 + 2W = 104
\n" ); document.write( "2W + 2W = 104 + 12
\n" ); document.write( "4W = 116
\n" ); document.write( "W = 116/4
\n" ); document.write( "W = 29 inches is the width
\n" ); document.write( "then
\n" ); document.write( "L = W - 6
\n" ); document.write( "L = 29 - 6
\n" ); document.write( "L = 23 inches is length
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\n" ); document.write( "Check this, find the perimeter with these values
\n" ); document.write( "2(23) + 2(29) =
\n" ); document.write( "46 + 58 = 104 \n" ); document.write( "
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