document.write( "Question 590740: John left his house and drove toward
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document.write( "km/h. Rob left some time later driving in
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document.write( "the same direction at an average speed of 48
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document.write( "km/h. After driving for five hours Rob
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document.write( "caught up with John. How long did John
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document.write( "drive before Rob caught up?
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Algebra.Com's Answer #375241 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! 40*(5+t)=48*5 \n" ); document.write( "40*5+40t=48*5 \n" ); document.write( "40t=8*5 \n" ); document.write( "40t=40 \n" ); document.write( "t=1 hour \n" ); document.write( "John left one hour before Rob did. \n" ); document.write( "It took John 6 hours to meetup with Rob. \n" ); document.write( "Rob drove 5 hours.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |