document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=590442>Question 590442</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello, I was wondering if you could please help me evalute this logarithmic problem. I have a decent knowledge of the subject; however, I can am flustered by this problem.\r<BR>\n" );
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document.write( "The instructions are \"Solve the equation\".\r<BR>\n" );
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document.write( "1/3(6)^(-4x)+1=6\r<BR>\n" );
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document.write( "Thank you for your time. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #375162 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=375162\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1/3(6)^(-4x)+1=6 \r<BR>\n" );
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document.write( "i think your equation is this:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%281%2F3%29%2A%286%29%5E%28-4x%29%2B1+=+6 ALIGN=MIDDLE  ALT=\"%281%2F3%29%2A%286%29%5E%28-4x%29%2B1+=+6\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "if so, then you would solve it as follows:\r<BR>\n" );
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document.write( "subtract 1 from both sides of the equation and then multiply both sides of the equation by 3 to get:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%286%29%5E%28-4x%29+=+15 ALIGN=MIDDLE  ALT=\"%286%29%5E%28-4x%29+=+15\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "take the log of both sides of this equation to get:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log%28%286%29%5E%28-4x%29%29+=+log%28%2815%29%29 ALIGN=MIDDLE  ALT=\"log%28%286%29%5E%28-4x%29%29+=+log%28%2815%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "since log(x^a) = a*log(x), this equation becomes:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-4x+%2A+log%28%286%29%29+=+log%28%2815%29%29 ALIGN=MIDDLE  ALT=\"-4x+%2A+log%28%286%29%29+=+log%28%2815%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "divide both sides of this equation by <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log%28%286%29%29 ALIGN=MIDDLE  ALT=\"log%28%286%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > to get:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-4x+=+log%28%2815%29%29%2Flog%28%286%29%29 ALIGN=MIDDLE  ALT=\"-4x+=+log%28%2815%29%29%2Flog%28%286%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "this becomes:\r<BR>\n" );
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document.write( "-4x = 1.511391594\r<BR>\n" );
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document.write( "divide both sides of this by -4 to get:\r<BR>\n" );
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document.write( "x = -.0377847899\r<BR>\n" );
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document.write( " </SPAN>\n" );
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