document.write( "Question 590300: Please Help me.\r
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document.write( "write an equation and graph it\r
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document.write( "1.) A quadratic function with x-intercept (3,0)and(-6,0)and y-intercept (0,-5)\r
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document.write( "5.) A cubic function with x-intercept (1,0)(-1/2,0)and(1/4,0)and y-intercept(0,2)\r
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Algebra.Com's Answer #375128 by KMST(5328)![]() ![]() You can put this solution on YOUR website! 1.) \n" ); document.write( "A quadratic polynomial with zeros at x=3 and x=-6, must have (x-3) and (x+6) as factors (and no other factor involving x). \n" ); document.write( "So, it would be \n" ); document.write( " \n" ); document.write( "For x=0, \n" ); document.write( " \n" ); document.write( "You know the graph is a prabola, you know the intercepts,and you know that it opens up because the leading coefficient (5/18) is positive. \n" ); document.write( "The axis of symmetry of the parabola has to be exactly halfway between its zeros, at \n" ); document.write( "The minimum (vertex) of the parabola has \n" ); document.write( "and \n" ); document.write( "Graphing parabolas, with all that information is easy. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "2.) For the second function it would be \n" ); document.write( " \n" ); document.write( "We do not need to do the whole multiplication to figure out that the independent term (you may call it constant) is \n" ); document.write( "For x=0, \n" ); document.write( "The function is \n" ); document.write( "Its zeros are -1/2, 1/4 and 1, and are the points were it changes sign. \n" ); document.write( "It is negative for \n" ); document.write( "positive for \n" ); document.write( "negative for \n" ); document.write( "and positive for \n" ); document.write( " GRAPHING: \n" ); document.write( "Depending on what you are being taught in class is how you would graph the function in problem 2. \n" ); document.write( "If they are teaching you the use of a graphing calculator or some graphing program, you would use that. \n" ); document.write( "If your class is calculus, you would find the derivative, and locate maxima and minima. \n" ); document.write( "Otherwise, you may calculate the value of the function for a few values of x (maybe x=-1, x=1/2, and x=2), plot those points and the intercepts, and sketch a curve that reasonable passes through all those points. \n" ); document.write( "This website will graph for me. \n" ); document.write( " |