document.write( "Question 590348: Hello,\r
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document.write( "How do you set up an equation in algebra to show that the width of a rectangle is 3 ft shorter than the length and that the perimeter of the rectangle is 86 feet?\r
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document.write( "86=3w -6\r
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document.write( "I am soooo confused! Please help!\r
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document.write( "bmccain@wowway.com \n" );
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Algebra.Com's Answer #375114 by Theo(13342) You can put this solution on YOUR website! L = length of rectangle \n" ); document.write( "W = width of rectangle \n" ); document.write( "W = L - 3 \n" ); document.write( "P = perimeter = 86 feet. \n" ); document.write( "formula for perimeter: \n" ); document.write( "2L + 2W = 86 \n" ); document.write( "substitute L-3 for W to get: \n" ); document.write( "2L + 2(L-3) = 86 \n" ); document.write( "simplify by removing parentheses to get: \n" ); document.write( "2L + 2L - 6 = 86 \n" ); document.write( "combine like terms to get: \n" ); document.write( "4L - 6 = 86 \n" ); document.write( "add 6 to both sides to get: \n" ); document.write( "4L = 92 \n" ); document.write( "divide both sides by 4 to get: \n" ); document.write( "L = 23 \n" ); document.write( "since W = L - 3, then: \n" ); document.write( "W = 20 \n" ); document.write( "formula for perimeter is: \n" ); document.write( "2L + 2W = 86 \n" ); document.write( "substitute for L and W to get: \n" ); document.write( "2*23 + 2*20 = 86 \n" ); document.write( "simplify to get: \n" ); document.write( "46 + 40 = 86 \n" ); document.write( "combine like terms to get: \n" ); document.write( "86 = 86 \n" ); document.write( "values for L and W are good. \n" ); document.write( " \n" ); document.write( " |