document.write( "Question 590347: i have to work out the two solutions of the angle of two isosceles triangles with areas of 4cm squared and sides of 4.7 (no base length given)
\n" ); document.write( "i know how to work out the area but i cannot rearrange the equation 1/2ab x SinC to help me answer this question, please explain and give the two answers
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Algebra.Com's Answer #375112 by scott8148(6628)\"\" \"About 
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(1/2)bh = 4 ___ h = 8 / b\r
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\n" ); document.write( "\n" ); document.write( "b^2 + h^2 = 4.7^2\r
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\n" ); document.write( "\n" ); document.write( "substituting ___ b^2 + (64 / b^2) = 4.7^2\r
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\n" ); document.write( "\n" ); document.write( "(b^2)^2 + 64 = 22.09 b^2 ___ (b^2)^2 - 22.09 b^2 + 64 = 0\r
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\n" ); document.write( "\n" ); document.write( "use quadratic formula to find b^2, then find b (two of the four solutions will not work)\r
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\n" ); document.write( "\n" ); document.write( "cos(C) = (b/2) / 4.7
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