document.write( "Question 590109: its a right triangle side A=X, side B=12 and the hypotenuse=6+X and im supposed to solve for x but when i set it up the x's keep cancelling out and equaling zero, how do i solve this, please help \n" ); document.write( "
Algebra.Com's Answer #375071 by mathhelp@(10)![]() ![]() ![]() You can put this solution on YOUR website! its a right triangle side A=X, side B=12 and the hypotenuse=6+X and im supposed to solve for x but when i set it up the x's keep cancelling out and equaling zero, how do i solve this, please help\r \n" ); document.write( "\n" ); document.write( "use the formula:\r \n" ); document.write( "\n" ); document.write( "a^2+b^2=c^2\r \n" ); document.write( "\n" ); document.write( "so your a = x \n" ); document.write( "b=12 \n" ); document.write( "c=6+x\r \n" ); document.write( "\n" ); document.write( "x^2+144=(6+x)^2\r \n" ); document.write( "\n" ); document.write( "expand:\r \n" ); document.write( "\n" ); document.write( "x^2+144=x^2+12x+36\r \n" ); document.write( "\n" ); document.write( "x^2+108=x^2+12x\r \n" ); document.write( "\n" ); document.write( "cancel out the x^2\r \n" ); document.write( "\n" ); document.write( "108=12x\r \n" ); document.write( "\n" ); document.write( "x=9\r \n" ); document.write( "\n" ); document.write( "so your answer should be:\r \n" ); document.write( "\n" ); document.write( "a=9\r \n" ); document.write( "\n" ); document.write( "b=12\r \n" ); document.write( "\n" ); document.write( "c=15\r \n" ); document.write( "\n" ); document.write( "test if this is valid:\r \n" ); document.write( "\n" ); document.write( "9^2+12^2<=15^2\r \n" ); document.write( "\n" ); document.write( "81+144<=225\r \n" ); document.write( "\n" ); document.write( "255=255\r \n" ); document.write( "\n" ); document.write( "Enjoy :) \n" ); document.write( " |