document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=55246>Question 55246</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 4 cm more than the width. The area is 45 cm ^ 2. Find the length and width. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #37504 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=37504\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The length =L SAY of a rectangle is 4 cm more than the width =W SAY. The area is 45 cm ^ 2. Find the length and width.<BR>\n" );
document.write( "L=W+4<BR>\n" );
document.write( "AREA = LW = (W+4)W =45<BR>\n" );
document.write( "W^2+4W-45=0<BR>\n" );
document.write( "W^2+9W-5W-45=0<BR>\n" );
document.write( "W(2+9)-5(W+9)=0<BR>\n" );
document.write( "(W-5)(W+9)=0<BR>\n" );
document.write( "W-5=0...OR...W=5<BR>\n" );
document.write( "HENCE L=4+5=9 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );