document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=590108>Question 590108</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi, I've been having trouble with logarithms, i tried to solve the problem below but i'm not sure if it's correct.<BR>\n" );
document.write( "ln3x-ln15=2\r<BR>\n" );
document.write( "\n" );
document.write( "How i tried to solve: \r<BR>\n" );
document.write( "\n" );
document.write( "ln3x-ln15=2\r<BR>\n" );
document.write( "\n" );
document.write( "ln3x divided by ln 15 = 2 <BR>\n" );
document.write( "then i crossed out ln with e  <BR>\n" );
document.write( "divided the 15 & 3 =5x<BR>\n" );
document.write( "and i got x=2 over 5 e\r<BR>\n" );
document.write( "\n" );
document.write( "Hopefully, that made sense. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #375029 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=375029\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ln3x-ln15=2\r<BR>\n" );
document.write( "\n" );
document.write( "How i tried to solve: \r<BR>\n" );
document.write( "\n" );
document.write( "ln3x-ln15=2\r<BR>\n" );
document.write( "\n" );
document.write( "ln3x divided by ln 15 = 2<BR>\n" );
document.write( "It says minus, you can't change it to divide.<BR>\n" );
document.write( "-----------------------------<BR>\n" );
document.write( "ln3x-ln15=2<BR>\n" );
document.write( "Logs are exponents.  Subtracting exponents --> dividing the arguments.<BR>\n" );
document.write( "--> ln(3x/15) = 2<BR>\n" );
document.write( "ln(x/5) = 2<BR>\n" );
document.write( "---------------<BR>\n" );
document.write( "The base of ln's, natural logs, is e.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=e%5E%28ln%28x%2F5%29%29+=+e%5E2 ALIGN=MIDDLE  ALT=\"e%5E%28ln%28x%2F5%29%29+=+e%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%2F5+=+e%5E2 ALIGN=MIDDLE  ALT=\"x%2F5+=+e%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+5%2Ae%5E2 ALIGN=MIDDLE  ALT=\"x+=+5%2Ae%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "----------------<BR>\n" );
document.write( "================<BR>\n" );
document.write( "email via the Thank You note if you have any questions.<BR>\n" );
document.write( "--------------------------------------------------------<BR>\n" );
document.write( "then i crossed out ln with e  <BR>\n" );
document.write( "divided the 15 & 3 =5x<BR>\n" );
document.write( "and i got x=2 over 5 e<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );