document.write( "Question 590084: A gas station sells 900 gallons of gasoline per hour if it charges $ 2.15 per gallon but only 800 gallons per hour if it charges $ 2.40 per gallon. Assuming a linear model\r
\n" ); document.write( "\n" ); document.write( "(a) How many gallons would be sold per hour of the price is $ 2.35 per gallon?
\n" ); document.write( "(b) What must the gasoline price be in order to sell 1600 gallons per hour?
\n" ); document.write( "(c) Compute the revenue taken at the four prices mentioned in this problem -- $ 2.15 , $ 2.35 , $ 2.40 and your answer to part (b). Which price gives the most revenue? \n" ); document.write( "

Algebra.Com's Answer #375027 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"+g+\"$ = gallons of gas sold per hour
\n" ); document.write( "Let $\"+p+\"$ = price per gallon in dollars
\n" ); document.write( "Plot $\"+g+\"$ on the vertical axis
\n" ); document.write( "Plot $\"+p+\"$ on the horizontal
\n" ); document.write( "use the point slope formula
\n" ); document.write( " $\"+%28+g+-+800+%29+%2F+%28+p+-+2.4+%29+=+%28+900+-+800+%29+%2F+%28+2.15+-+2.4+%29+\"$
\n" ); document.write( " $\"+%28+g+-+800+%29+%2F+%28+p+-+2.4+%29+=+100+%2F+%28-.25%29+\"$
\n" ); document.write( " $\"+%28+g+-+800+%29+%2F+%28+p+-+2.4+%29+=+-400+\"$
\n" ); document.write( " $\"+g+-+800+=+-400%2A%28+p+-+2.4+%29+\"$
\n" ); document.write( " $\"+g+-+800+=+-400p+%2B+960+\"$
\n" ); document.write( " $\"+g+=+-400p+%2B+1760+\"$
\n" ); document.write( "--------------------
\n" ); document.write( "(a)
\n" ); document.write( " $\"+g+=+-400%2A2.35+%2B+1760+\"$
\n" ); document.write( " $\"+g+=+-940+%2B+1760+\"$
\n" ); document.write( " $\"+g+=+820+\"$
\n" ); document.write( "820 gallons/hr would be sold
\n" ); document.write( "-----------------------
\n" ); document.write( "(b)
\n" ); document.write( " $\"+g+=+-400p+%2B+1760+\"$
\n" ); document.write( " $\"+1600+=+-400p+%2B+1760+\"$
\n" ); document.write( " $\"+400p+=+1760+-+1600+\"$
\n" ); document.write( " $\"+400p+=+160+\"$
\n" ); document.write( " $\"+p+=+.4+\"$
\n" ); document.write( "The price must be $ .40 / gallon to sell 1600 gallons/hr
\n" ); document.write( "-----------------------
\n" ); document.write( "(c)
\n" ); document.write( "(1) $\"+2.15%2A900+=+1935+\"$
\n" ); document.write( "Revenue = $ 1,935
\n" ); document.write( "(2) $\"+2.4%2A800+=+1920+\"$
\n" ); document.write( "Revenue = $ 1,920
\n" ); document.write( "(3) $\"+2.35%2A820+=+1927+\"$
\n" ); document.write( "Revenue = $ 1,927
\n" ); document.write( " $\"+.4%2A1600+=+640+\"$
\n" ); document.write( "Revenue = $640
\n" ); document.write( "$2.15 / gallon gives the most revenue \n" ); document.write( "

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