document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=589686>Question 589686</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A woman is twice as old as her daughter. Five years ago the sum of their ages was 44. What are their present ages? I came up with x being the daughters age and 2x as the mothers age so i put it into the equation <BR>\n" );
document.write( "x+5+2x+5=44<BR>\n" );
document.write( "3x=54<BR>\n" );
document.write( "x=18<BR>\n" );
document.write( "mums age:36<BR>\n" );
document.write( "daughters age:18<BR>\n" );
document.write( "but i dont know if this their current age or their age five years ago im confused can u please help me!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #374942 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=374942\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let d = the present age of the daughter<BR>\n" );
document.write( "Then the mother's current age = 2d<BR>\n" );
document.write( "5 years ago the daughter's age was d - 5 and the mother's age was 2d - 5<BR>\n" );
document.write( "The sum of their ages 5 yrs ago was 44:<BR>\n" );
document.write( "d - 5 + (2d - 5) = 44<BR>\n" );
document.write( "3d - 10 = 44<BR>\n" );
document.write( "3d = 54<BR>\n" );
document.write( "d = 18<BR>\n" );
document.write( "So the daughter is 18 and the mother is 36 years old<BR>\n" );
document.write( "Note that you had the correct answer, but you set up and solved your equations incorrectly! </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );