document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=589614>Question 589614</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the value of tan (a+b) if sin a = -5/13, cos b = 4/5    <BR>\n" );
document.write( "270 degrees < a < 360 degrees<BR>\n" );
document.write( "270 degrees < b <360 degrees\r<BR>\n" );
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document.write( "Thank you so much! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #374934 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=374934\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the value of tan (a+b) if sin a = -5/13, cos b = 4/5 <BR>\n" );
document.write( "270 degrees < a < 360 degrees (quadrant IV)<BR>\n" );
document.write( "270 degrees < b <360 degrees (quadrant IV)<BR>\n" );
document.write( "**<BR>\n" );
document.write( "use tan addition formula:<BR>\n" );
document.write( "tan(a+b)=(tan a+tan b)/1-tan a*tan b<BR>\n" );
document.write( "if sin a=-5/13<BR>\n" );
document.write( "tan a=-5/12<BR>\n" );
document.write( "if cos b=4/5<BR>\n" );
document.write( "tan b=-3/4<BR>\n" );
document.write( "..<BR>\n" );
document.write( "tan(a+b)=(-5/12-3/4)/1-5/12*3/4<BR>\n" );
document.write( "tan(a+b)=(-14/12/1-15/48<BR>\n" );
document.write( "tan(a+b)=(-14/12)/(33/48)&#8776;-1.7<BR>\n" );
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