document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=589608>Question 589608</A>: <I><SPAN STYLE=\"word-break: break-all;\"> So confused on this! Help would be so appreciated<BR>\n" );
document.write( "Simplify (1-cos^2 (theta))/ (1+cot^2 (theta))<BR>\n" );
document.write( "THANK YOU!!!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #374933 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=374933\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Simplify (1-cos^2 (theta))/ (1+cot^2 (theta))<BR>\n" );
document.write( "use x for theta<BR>\n" );
document.write( "(1-cos^2x)/(1+cot^2x)<BR>\n" );
document.write( "(1-cos^2x)/(1+cos^2x/sin^2x)<BR>\n" );
document.write( "(1-cos^2x)/(sin^2x+cos^2x)/sin^2x)<BR>\n" );
document.write( "(1-cos^2x)/(1/(sin^2x))<BR>\n" );
document.write( "(1-cos^2x)/(1/(1-cos^2x))<BR>\n" );
document.write( "(1-cos^2x)^2<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );