document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=589609>Question 589609</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I don't understand how to solve this problem, please help me find the steps to solve this problem.\r<BR>\n" );
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document.write( "The measure of the second angle of a triangle is 50 more than that of the first. The measure of the third angle is 10 less than twice the first. Find the measure of the angles. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #374908 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=374908\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let one angle be x deg<BR>\n" );
document.write( "second angle = x+50 deg<BR>\n" );
document.write( "Third angle = 2x-10\r<BR>\n" );
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document.write( "sum of all angles of triangle = 180 deg\r<BR>\n" );
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document.write( "x+x+50+2x-10=180\r<BR>\n" );
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document.write( "4x+40=180\r<BR>\n" );
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document.write( "4x=180-40<BR>\n" );
document.write( "4x= 140\r<BR>\n" );
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document.write( "/4<BR>\n" );
document.write( "x=35 \r<BR>\n" );
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document.write( "Plug x in the angles\r<BR>\n" );
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document.write( "first angle 35<BR>\n" );
document.write( "second = 85<BR>\n" );
document.write( "third = 60<BR>\n" );
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