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You can put this solution on YOUR website!
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document.write( "Find four consecutive odd integers such that the sum of the second \r\n" );
document.write( "and the fourth is 63 more than one-fifth of the third.....that's my\r\n" );
document.write( "question...can you show the solution?????\r\n" );
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document.write( "\"Four consecutive odd integers\" refers to the set {1,3,5,7} or\r\n" );
document.write( "the set {3,5,7,9} or the set {9,11,13,15} or the set {77,79,81,83} or\r\n" );
document.write( "any set of four such odd numbers in a row. \r\n" );
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document.write( "To work such problems you start out by\r\n" );
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document.write( "1. letting x represent the smallest of four consecutive odd integers.\r\n" );
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document.write( "2. Then x+2 represents the second of four consecutive odd integers,\r\n" );
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document.write( "3. Then x+4 represents the third of four consecutive odd integers.\r\n" );
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document.write( "4. Then x+6 represents the fourth of four consecutive odd integers\r\n" );
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document.write( ">>...the sum of the second and the fourth is 63 more than one-fifth \r\n" );
document.write( "of the third...<<\r\n" );
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document.write( "Replace the words \"the sum of the second and the fourth\" by\r\n" );
document.write( "(x+2) + (x+6)\r\n" );
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document.write( "So we have\r\n" );
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document.write( ">>...(x+2) + (x+6) is 63 more than one-fifth of the third...<<\r\n" );
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document.write( "Replace the words \"one-fifth of the third\" by \"(1/5)(x+4)\" \r\n" );
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document.write( "So we now have\r\n" );
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document.write( ">>...(x+2) + (x+6) is 63 more than (1/5)(x+4)...<< \r\n" );
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document.write( "To get 63 more than (1/5)(x+4) we add 63 to it, so replace\r\n" );
document.write( "the words \"63 more than (1/5)(x+4)\" by \"(1/5)(x+4) + 63\" \r\n" );
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document.write( "So now we have\r\n" );
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document.write( ">>...(x+2) + (x+6) is (1/5)(x+4) + 63...<< \r\n" );
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document.write( "Finally replace the word \"is\" by \"=\" and we have completely\r\n" );
document.write( "gotten rid of the English, and all that's left is algebra:\r\n" );
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document.write( "(x+2) + (x+6) = (1/5)(x+4) + 63\r\n" );
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document.write( "To solve that first multiply every term by LCD = 5. That is,\r\n" );
document.write( "put 5 as a multiplier in front of every term on both sides\r\n" );
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document.write( "5(x+2) + 5(x+6) = 5(1/5)(x+4) + 5(63)\r\n" );
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document.write( "Replace the 5(1/5) on the right by 1, and the 5(63) by 315\r\n" );
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document.write( "5(x+2) + 5(x+6) = 1(x+4) + 315\r\n" );
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document.write( "Now distribute to remove parentheses, combine like signs,\r\n" );
document.write( "solve, and you get\r\n" );
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document.write( "x = 31\r\n" );
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document.write( "So since the four cnsecutive integers are x, x+2, x+4 and x+6,\r\n" );
document.write( "are respectively 31, 33, 35 and 37\r\n" );
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document.write( "Edwin \n" );
document.write( "