document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=589466>Question 589466</A>: <I><SPAN STYLE=\"word-break: break-all;\"> For the sequence, describe the pattern, write the next term, and write a rule for the nth term.<BR>\n" );
document.write( "-2,05,-8,-11,... </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #374874 by </B><A HREF=/tutors/aboutme.mpl?userid=KMST><B>KMST(5328)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=KMST><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=KMST><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=374874\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If you fat-fingered that zero and your sequence was really -2, -5, -8, -11, then each term is found by adding -3 to the previous one, so<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a%5Bn%2B1%5D=a%5Bn%5D-3 ALIGN=MIDDLE  ALT=\"a%5Bn%2B1%5D=a%5Bn%5D-3\"   DISABLED_style= \"max-width:90%; height:auto;\" > (recursive formula) and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a%5Bn%5D=-2-3%28n-1%29 ALIGN=MIDDLE  ALT=\"a%5Bn%5D=-2-3%28n-1%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );