document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=589483>Question 589483</A>: <I><SPAN STYLE=\"word-break: break-all;\"> i am doing solving systems by elimination and i don't understand how to the problem. it is 3x-y=-2 and -2x+2y=8 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #374862 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=374862\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (1) 3x-y=-2 <BR>\n" );
document.write( "(2) -2x+2y=8<BR>\n" );
document.write( "multiply 3x-y=-2  by 2<BR>\n" );
document.write( "(1a) 6x-2y=-4<BR>\n" );
document.write( "add (1a) to second (2) equation<BR>\n" );
document.write( "-2x+2y=8<BR>\n" );
document.write( "6x-2y=-4<BR>\n" );
document.write( "4x=4<BR>\n" );
document.write( "x=1<BR>\n" );
document.write( "substitute x=1 into any of the three equations<BR>\n" );
document.write( "-2x+2y=8<BR>\n" );
document.write( "-2+2y=8<BR>\n" );
document.write( "add 2<BR>\n" );
document.write( "2y=10<BR>\n" );
document.write( "y=5<BR>\n" );
document.write( "solution<BR>\n" );
document.write( "x=1<BR>\n" );
document.write( "y=5<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );