document.write( "Question 589283: given the endpoints of the diameter of the circle are (-8,4) and (-4,8). write the equation of the circle \n" ); document.write( "
Algebra.Com's Answer #374834 by lwsshak3(11628)\"\" \"About 
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given the endpoints of the diameter of the circle are (-8,4) and (-4,8). write the equation of the circle
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\n" ); document.write( "Standard form of equation for circle: (x-h)^2+(y-k)^2=r^2, (h,k) being the (x,y) coordinates of the center, r=radius.
\n" ); document.write( "use midpoint formula to find center:
\n" ); document.write( "(x1+x2)/2, (y1+y2)/2
\n" ); document.write( "(-8-4)/2/(4+8)/2=(-6,6)
\n" ); document.write( "center: (-6,6)
\n" ); document.write( "use distance formula to find diameter:
\n" ); document.write( "d^2=(x1-x2)^2+(y1-y2)^2
\n" ); document.write( "d^2=(-8+4)^2+(4-8)^2
\n" ); document.write( "d^2=16+16=32
\n" ); document.write( "d=√32
\n" ); document.write( "radius=√32/2
\n" ); document.write( "r^2=32/4=8
\n" ); document.write( "Equation of given circle:
\n" ); document.write( "(x+6)^2+(y-6)^2=8
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