document.write( "Question 589050: Kate is three years less than twice as old as her brother Brett. Next year, Brett's age will be three fourths Kate's age. How old is each now? \n" ); document.write( "
Algebra.Com's Answer #374783 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
let k = K's present age
\n" ); document.write( "let b = B's present age
\n" ); document.write( ";
\n" ); document.write( "Write an equation for each statement:
\n" ); document.write( ":
\n" ); document.write( "\"Kate is three years less than twice as old as her brother Brett.\"
\n" ); document.write( "k = 2b-3
\n" ); document.write( ":
\n" ); document.write( "\" Next year, Brett's age will be three fourths Kate's age.\"
\n" ); document.write( "b + 1 = .75(k+1)
\n" ); document.write( "b + 1 = .75k + .75
\n" ); document.write( "b = .75k + .75 - 1
\n" ); document.write( "b = .75k -.25
\n" ); document.write( "Replace k with (2b-3)
\n" ); document.write( "b = .75(2b-3) - .25
\n" ); document.write( "b = 1.5b - 2.25 - .25
\n" ); document.write( "b = 1.5b - 2.5
\n" ); document.write( "2.5 = 1.5b - b
\n" ); document.write( "2.5 = .5b
\n" ); document.write( "multiply both sides by 2
\n" ); document.write( "b = 5 yrs is B's age
\n" ); document.write( "then
\n" ); document.write( "k = 2(5) - 3
\n" ); document.write( "k = 7 yrs is K's age
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check solutions in the statement:
\n" ); document.write( "\" Next year, Brett's age will be three fourths Kate's age.\"
\n" ); document.write( "5 + 1 = .75(7+1)
\n" ); document.write( "6 = .75(8)\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );