document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=589026>Question 589026</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The mass of a radioactive element at time x is given by the equation below, where c is the original mass and h is the half-life of the element. How old is a mummy that has lost 55% of its carbon-14 (its half-life is 5730 years)? (Round your answer to the nearest year.)<BR>\n" );
document.write( "                  Formula given M(x)= c(.5^x/h) <BR>\n" );
document.write( "Please help me solve this problem please. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #374782 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=374782\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The mass of a radioactive element at time x is given by the equation below,<BR>\n" );
document.write( " where <BR>\n" );
document.write( " c is the original mass and <BR>\n" );
document.write( " h is the half-life of the element. <BR>\n" );
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document.write( "How old is a mummy that has lost 55% of its carbon-14 (its half-life is 5730 years)? (Round your answer to the nearest year.)<BR>\n" );
document.write( "><BR>\n" );
document.write( "Formula given M(x)= c(.5^x/h) <BR>\n" );
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document.write( "Let the original amt of carbon = 1<BR>\n" );
document.write( "then<BR>\n" );
document.write( "1-.55 = .45 remains<BR>\n" );
document.write( "Find x, years of decay<BR>\n" );
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document.write( "1*.5^(x/5730) = .45<BR>\n" );
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document.write( "Use natural logs<BR>\n" );
document.write( "ln*(.5^(x/5730)) = ln(.45)<BR>\n" );
document.write( ";<BR>\n" );
document.write( "log equiv of exponents<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%2F5730 ALIGN=MIDDLE  ALT=\"x%2F5730\"   DISABLED_style= \"max-width:90%; height:auto;\" >ln(.5) = ln(.45}<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%2F5730 ALIGN=MIDDLE  ALT=\"x%2F5730\"   DISABLED_style= \"max-width:90%; height:auto;\" > = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=ln%28.45%29%2Fln%28.5%29 ALIGN=MIDDLE  ALT=\"ln%28.45%29%2Fln%28.5%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( ":<BR>\n" );
document.write( "use your calc<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%2F5730 ALIGN=MIDDLE  ALT=\"x%2F5730\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 1.152<BR>\n" );
document.write( "x = 1.152*5730<BR>\n" );
document.write( "x = 6601 yrs<BR>\n" );
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document.write( "Check this on your calc; enter: .5^(6601/5730) ~ .45 which 45% remaining<BR>\n" );
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