document.write( "Question 589266: a boat trip trip 10 miles down a river takes you 1 hour and 15 minutes but it takes 4 hours to return.... whats the speed of the boat in still water and the speed of the current \n" ); document.write( "
Algebra.Com's Answer #374776 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Use distance equals rate times time, from which you can derive rate equals distance divided by time.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "To go downstream it takes 1.25 (1 hour 15 minutes is 1 and 1 quarter hour) hours to go 10 miles. 10 divided by 1.25 is 8, so the rate of the boat in still water PLUS the rate of the current is 8 miles per hour.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "To go upstream it takes 4 hours to go 10 miles. 10 divided by 4 is 2.5, so the rate of the boat in still water MINUS the rate of the current is 2.5 miles per hour.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Set up your 2X2 system of equations:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Use the elimination method to solve for \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |