document.write( "Question 55168: Express 2x^2+2y^2-12x+16y=-32 in standard form for a circle. Identify the radius and center of the circle. \n" ); document.write( "
Algebra.Com's Answer #37475 by venugopalramana(3286)\"\" \"About 
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Express 2x^2+2y^2-12x+16y=-32.DIVIDING BY 2
\n" ); document.write( "x^2+y^2-6x+8y=-16
\n" ); document.write( "[X^2-2(X)(3)+3^2]-3^2+[Y^2+2(Y)(4)+4^2]-4^2=-16
\n" ); document.write( "(X-3)^2+(Y+2)^2=9=3^2
\n" ); document.write( "THIS IS IN THE STD.FORM OF
\n" ); document.write( "(X-H)^2+(Y-K)^2=R^2
\n" ); document.write( "HENCE CENTRE = (H,K) = (3,-2)
\n" ); document.write( "RADIUS = R =3\r
\n" ); document.write( "\n" ); document.write( "in standard form for a circle. Identify the radius and center of the circle.
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