document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=589185>Question 589185</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I solve<BR>\n" );
document.write( "5^x=1/125?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #374747 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=374747\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How do I solve<BR>\n" );
document.write( "5^x=1/125?<BR>\n" );
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document.write( "If you recognize that 125 = 5^3, then 5^(-3) = 1/125<BR>\n" );
document.write( "--> x = -3<BR>\n" );
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document.write( "If not,<BR>\n" );
document.write( "x*log(5) = log(1/125)<BR>\n" );
document.write( "x = log(1/125)/log(5)<BR>\n" );
document.write( "x = -3<BR>\n" );
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document.write( "If it's a random number, eg, 5^x = 1/126 then you have to use the 2nd method.<BR>\n" );
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