document.write( "Question 589150: Hello, I need help on a rational equation problem. 5/4 = n-3/n-4 I do realize that you either have to turn it into 4(5/4 = n-3/n-4) or n-4(5/4 = n-3/n-4) but I am sadly unsure of exactly how to do this correctly. I thought perhaps it would turn into 5 = 4n-3/4n-4 but that doesn't seem correct to me. Nor does (n-4)(5/4) = n-3 I'm really struggling with these and I have a test on Friday. Thank you for your help. \n" ); document.write( "
Algebra.Com's Answer #374739 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
Think \"cross-multiply\"
\n" ); document.write( "5/4 = (n-3)/(n-4)
\n" ); document.write( "5(n-4) = 4(n-3)
\n" ); document.write( "5n-20 = 4n-12
\n" ); document.write( "n-20 = -12
\n" ); document.write( "n = 8\r
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