document.write( "Question 55197This question is from textbook 
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document.write( ":  Can you please help me? This problem isn't in the book.
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document.write( "3(y-2)+y(1+2)=4
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document.write( "3y-6+1y+2y=4
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document.write( "then what?
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document.write( "6y-6=4-6???? what's after that??? \n" );
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| Algebra.Com's Answer #37473 by anjulasahay(30)      You can put this solution on YOUR website! Can you please help me? This problem isn't in the book. \n" ); document.write( "3(y-2)+y(1+2)=4 \n" ); document.write( "3y-6+1y+2y=4 \n" ); document.write( "then what? \n" ); document.write( "6y-6=4-6???? what's after that??? \n" ); document.write( "ans: \n" ); document.write( " 3(y-2)+y(1+2) = 4 \n" ); document.write( "or 3y-6+y(3)= 4 \n" ); document.write( "or 6y-6 = 4 \n" ); document.write( "or 6y = 4 + 6 = 10 \n" ); document.write( "or y = 10/6 = 5/3\r \n" ); document.write( "\n" ); document.write( "note : \n" ); document.write( " 6y-6=4-6???? --- how u arrived at this because 4-6 is not valid . \n" ); document.write( " you will move -6 from left to right side where it will have + sign \n" ); document.write( " or you can understand like this \n" ); document.write( " since both sides are equal you can add same number in both sides without affecting the values i.e. \n" ); document.write( " 6y-6=4 \n" ); document.write( " or 6y-6+6=4+6 \n" ); document.write( " or 6y = 4+6 \n" ); document.write( " or y = 10/6 = 5/3 \n" ); document.write( " \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |