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How do I graph the line and find the slope of (2,3) and (-6,-3)?
\n" ); document.write( "Standard form of equation for a straight line: y=mx+b, m=slope, b=y-intercept
\n" ); document.write( "For given points:
\n" ); document.write( "slope=∆y/∆x=(-3-3)/(-6-2)=-6/-8=3/4
\n" ); document.write( "equation:
\n" ); document.write( "y=(3/4)x+b
\n" ); document.write( "solving for b using coordinates of one of the given points (2,3)
\n" ); document.write( "3=(3/4)*2+b
\n" ); document.write( "3=3/2+b
\n" ); document.write( "b=3/2
\n" ); document.write( "equation of line:
\n" ); document.write( "y=3x/4+3/2
\n" ); document.write( "Graphing the line:
\n" ); document.write( "Starting from the first point on the line at the y-intercept (3/2), move 3 units up and 4 units to the right (rise/run) to find the second point on the line. \n" ); document.write( "