document.write( "Question 588929: 4/3d-5=2 \n" ); document.write( "
Algebra.Com's Answer #374698 by rfer(16322) ![]() You can put this solution on YOUR website! 4/3d=2+5 \n" ); document.write( "d=7/(4/3) \n" ); document.write( "d=7*3/4 \n" ); document.write( "d=21/4 \n" ); document.write( "d 5 1/4 \n" ); document.write( " |