document.write( "Question 588929: 4/3d-5=2 \n" ); document.write( "
Algebra.Com's Answer #374698 by rfer(16322)\"\" \"About 
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4/3d=2+5
\n" ); document.write( "d=7/(4/3)
\n" ); document.write( "d=7*3/4
\n" ); document.write( "d=21/4
\n" ); document.write( "d 5 1/4
\n" ); document.write( "
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