document.write( "Question 588770: If \"+sqrt+%28x%5E2+-5x+-11%29+%2B+13+=x+\", then what value is \"x%5E2-3x%2B3\" ? \n" ); document.write( "
Algebra.Com's Answer #374676 by KMST(5328)\"\" \"About 
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Something is wrong with the problem, or my interpretation.
\n" ); document.write( "I cannot find a real x that is a solution of that equation.
\n" ); document.write( "If there is no x, how could there be an \"x%5E2-3x%2B3\" ?
\n" ); document.write( "If \"+sqrt+%28x%5E2+-5x+-11%29+%2B+13+=x+\" <--> \"+sqrt+%28x%5E2+-5x+-11%29=x-13+\" and we are working in the real numbers,
\n" ); document.write( "then \"+x%5E2+-5x+-11%3E=0\" and \"x%3E=13\".
\n" ); document.write( "Then, squaring both sides, we get
\n" ); document.write( "\"x%5E2+-5x+-11=%28x-13%29%5E2+\" --> \"x%5E2+-5x+-11=x%5E2-26x%2B169\" --> \"-5x-11=-26x%2B169\" --> \"-5x-11%2B26x%2B11=-26x%2B169%2B26x%2B11\" --> \"21x=180\" --> \"x=180%2F21\" --> \"x=60%2F7\"
\n" ); document.write( "But that is only a solution of \"x%5E2+-5x+-11=%28x-13%29%5E2+\"
\n" ); document.write( "It is not a solution of \"+sqrt+%28x%5E2+-5x+-11%29+%2B+13+=x+\" <--> \"+sqrt+%28x%5E2+-5x+-11%29=x-13+\"
\n" ); document.write( "because it makes \"x-13%3C0\"
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