document.write( "Question 588897: I need help solving this math problem. Can you help me solve? Thank you. \r
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Algebra.Com's Answer #374675 by Edwin McCravy(20055) $\"\"$ $\"About$

You can put this solution on YOUR website!
If f(x) = 2x - x² + 1, find f(x-3)
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document.write( "f(x) = 2x - x² + 1\r
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document.write( "Replace all the x's by an open pair of parentheses, ( )'s\r
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document.write( "f(( )) = 2( ) - ( )² + 1\r
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document.write( "Open all the ( )'s a little wider:\r
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document.write( "f((  )) = 2(  ) - (  )² + 1\r
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document.write( "Place x-3 between each set of parentheses\r
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document.write( "f((x-3)) = 2(x-3) - (x-3)² + 1\r
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document.write( "Erase the redundant parentheses inside f((x-3)) and make it f(x-3)\r
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document.write( "f(x-3) = 2(x-3) - (x-3)² + 1\r
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document.write( "Leave the left side as it is, but simplify the right side:\r
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document.write( "f(x-3) = (2x-6) - (x-3)(x-3) + 1\r
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document.write( "f(x-3) = (2x-6) - (x²-6x+9) + 1\r
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document.write( "f(x-3) = 2x - 6 - x² + 6x - 9 + 1\r
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document.write( "f(x-3) = 8x - 14 - x²\r
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document.write( "That's the answer, or maybe you'd like to arrange it in
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document.write( "descending order:\r
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document.write( "f(x-3) = -x² + 8x - 14 \r
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document.write( "Edwin \n" );
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