document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=588867>Question 588867</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A photograph is 8in by 10in.<BR>\n" );
document.write( " A. Write an equation to find the amount x that should be added to the current length and width to double the area of the photograph.<BR>\n" );
document.write( " B. Solve the equation.<BR>\n" );
document.write( " C. What will the new dimensions be?\r<BR>\n" );
document.write( "\n" );
document.write( "Thank you soo much if you answer this.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #374653 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=374653\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The original area is 8*10 = 80 square inches.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "The doubled area is 80*2 = 160 square inches.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "The new dimensions are 8+x by 10+x and they multiply out to 160, so the equation is (8+x)(10+x) = 160\r<BR>\n" );
document.write( "\n" );
document.write( "-------------------------------------------------------<BR>\n" );
document.write( "b)\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Now get the equation into standard form\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "(8+x)(10+x) = 160\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "80+18x+x^2 = 160\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "80+18x+x^2 - 160 = 0\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "x^2 + 18x - 80 = 0\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Now use the quadratic formula to solve for x\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "x = (-b+-sqrt(b^2-4ac))/(2a)\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "x = (-(18)+-sqrt((18)^2-4(1)(-80)))/(2(1))\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "x = (-18+-sqrt(324-(-320)))/(2)\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "x = (-18+-sqrt(644))/2\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "x = (-18+sqrt(644))/2 or x = (-18-sqrt(644))/2\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "x = (-18+2*sqrt(161))/2 or x = (-18-2*sqrt(161))/2\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "and approximate the solutions above to get\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "x = 3.6885775 or x = -21.6885775\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "toss out the negative solution to get \r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "x = 3.6885775\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "So you should add about 3.6885775 inches to each dimension to double the area of the photograph.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "-------------------------------------------------------\r<BR>\n" );
document.write( "\n" );
document.write( "C)\r<BR>\n" );
document.write( "\n" );
document.write( "Add 8 and 3.6885775 to get 11.6885775. This is the new width\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Add 10 and 3.6885775 to get 13.6885775. This is the new length </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );