document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=55199>Question 55199</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the center and the radius of the circle whose equation is given: x^2+y^2+6x+8=0<BR>\n" );
document.write( "Center = (_,_)   Radius = _ </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #37465 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=37465\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the center and the radius of the circle whose equation is given: x^2+y^2+6x+8=0<BR>\n" );
document.write( "Rewrite as follows:<BR>\n" );
document.write( "x^2+6x+?+y^2 = -8+?<BR>\n" );
document.write( "Complete the square to get:<BR>\n" );
document.write( "x^2+6x+9 + y^2 = -8+9<BR>\n" );
document.write( "Factor to get:<BR>\n" );
document.write( "(x+3)^2 + (y-0)^2 = 1<BR>\n" );
document.write( "Center at (-3,0)<BR>\n" );
document.write( "Radius = 1<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );