document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=588846>Question 588846</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a yard in the shape of a square meaures 20ft on each side. a triangular area with a height of 6ft and a base of 5ft is dug up for a flower bed. how much yard area is left over? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #374646 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=374646\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Area of entire yard = 20*20 = 400 square feet\r<BR>\n" );
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document.write( "Area of triangle = (5*6)/2 = 30/2 = 15 square feet\r<BR>\n" );
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document.write( "Area left over = 400 - 15 = <font color=\"red\">385 square feet</font>. </SPAN>\n" );
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