document.write( "Question 588567: log(7)36-log(7)2x=log(7)4 \n" ); document.write( "
Algebra.Com's Answer #374631 by lwsshak3(11628)\"\" \"About 
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log(7)36-log(7)2x=log(7)4
\n" ); document.write( "log7(36)-log7(2x)-log7(4)=0
\n" ); document.write( "log7(36)-(log7(2x)+log7(4))=0
\n" ); document.write( "log7[36/2x*4]=0
\n" ); document.write( "convert to exponential form
\n" ); document.write( "7^0=36/8x=1
\n" ); document.write( "8x=36
\n" ); document.write( "x+36/8=9/2
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