document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=55199>Question 55199</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the center and the radius of the circle whose equation is given: x^2+y^2+6x+8=0<BR>\n" );
document.write( "Center = (_,_)   Radius = _ </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #37462 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=37462\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the center and the radius of the circle whose equation is given: x^2+y^2+6x+8=0<BR>\n" );
document.write( "[X^2+2(X)(3)+3^2]-3^2+Y^2+8=0<BR>\n" );
document.write( "(X+3)^2+Y^2=1<BR>\n" );
document.write( "COMPARING WITH STD EQN.<BR>\n" );
document.write( "(X-H)^2+(Y-K)^2 =R^2<BR>\n" );
document.write( "CENTRE = (H,K) = (-3,0)<BR>\n" );
document.write( "RADIUS =R =1\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Center = (_,_) Radius = _<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );