document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=588744>Question 588744</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A train leave Philadelphia at 1:00 pm. It's traveling at 65 mph towards Denver. Another train leaves Denver at 4:00 pm. It's traveling at 60 mph towards Philadelphia. If the distance between the two cities is 1725 miles and the trains are on the same track, when will they crash? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #374591 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=374591\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> There are at least three possibilities.<BR>\n" );
document.write( "1)They won't ever crash because the train conductors are not as ignorant as you or your teachers think.\r<BR>\n" );
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document.write( "2)if the times are not local times.<BR>\n" );
document.write( "65*(3+x)+60x=1725<BR>\n" );
document.write( "x = 306/25=12.24 hours\r<BR>\n" );
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document.write( "3)If the times are local then you have to adjust since Denver and Philadelphia are two hours apart.<BR>\n" );
document.write( "So add two hours to Denver to get equivalent Philadelphia time so there is only an hour difference now<BR>\n" );
document.write( "65*(1+x)+60x=1725<BR>\n" );
document.write( "x = 332/25=13.28 hours\r<BR>\n" );
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document.write( " </SPAN>\n" );
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