document.write( "Question 588594: log[b](8) + log[b](x^2) = log[b](x) \n" ); document.write( "
Algebra.Com's Answer #374551 by lwsshak3(11628)\"\" \"About 
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log[b](8) + log[b](x^2) = log[b](x)
\n" ); document.write( "logb(8) + logb(x^2) = logb(x)
\n" ); document.write( "logb(8) + logb(x^2) -logb(x)=0
\n" ); document.write( "place under single log
\n" ); document.write( "logb[8x^2/x]=logb(8x)=0
\n" ); document.write( "convert to exponential form: base(b) raised to log of number(0)=number(8x)
\n" ); document.write( "b^0=8x=1
\n" ); document.write( "x=1/8
\n" ); document.write( "note: This means b could be any base.
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