document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=588606>Question 588606</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve by method of substitution<BR>\n" );
document.write( "3x-6y=21<BR>\n" );
document.write( "3x+14=y\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #374547 by </B><A HREF=/tutors/aboutme.mpl?userid=kyawkhant><B>kyawkhant(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=kyawkhant><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=374547\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solution:\r<BR>\n" );
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document.write( "3x-6y= 21.........eqn(1)<BR>\n" );
document.write( "3x+14= y.........eqn(2)<BR>\n" );
document.write( "Substitute y in eqn (1)<BR>\n" );
document.write( "3x-6(3x+14)=21<BR>\n" );
document.write( "3x-18x-84=21<BR>\n" );
document.write( "-15x=21+84<BR>\n" );
document.write( "-15x=105<BR>\n" );
document.write( "   x=105/-15<BR>\n" );
document.write( "   x=-7<BR>\n" );
document.write( "x=-7, y=3(-7)+14<BR>\n" );
document.write( "      y=-21+14<BR>\n" );
document.write( "      y= -7<BR>\n" );
document.write( "Therefore, x=-7 and y=-7 </SPAN>\n" );
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