document.write( "Question 588251: How do i find the conic equation for 4(x+1)^2-2(y-3)^2=1 \n" ); document.write( "
Algebra.Com's Answer #374546 by lwsshak3(11628)\"\" \"About 
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How do i find the conic equation for
\n" ); document.write( "4(x+1)^2-2(y-3)^2=1
\n" ); document.write( "(x+1)^2/1/4-(y-3)^2/1/2=1
\n" ); document.write( "This is an equation of a hyperbola with horizontal transverse axis of the standard form:
\n" ); document.write( "(x-h)^2/a^2-(y-k)^2/b^2=1, (h,k) being the (x,y) coordinates of the center.
\n" ); document.write( "For given equation:
\n" ); document.write( "center: (-1,3)
\n" ); document.write( "a^2=1/4
\n" ); document.write( "b^2=1/2
\n" ); document.write( "
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