document.write( "Question 588579: 9x2 +14y = 0
\n" ); document.write( " Find focus, directrix, and focal diameter
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Algebra.Com's Answer #374544 by lwsshak3(11628)\"\" \"About 
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9x2 +14y = 0
\n" ); document.write( "Find focus, directrix, and focal diameter.
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\n" ); document.write( "Standard form of equation for a parabola that opens downwards: (x-h)^2=-4p(y-k), (h,k) being the (x,y) coordinates of the vertex.
\n" ); document.write( "For given equation: 9x^2+14y=0
\n" ); document.write( "9x^2=-14y
\n" ); document.write( "x^2=(-14/9)y
\n" ); document.write( "vertex: (0,0)
\n" ); document.write( "axis of symmetry: y-axis or x=0
\n" ); document.write( "4p=14/9
\n" ); document.write( "p=14/36=7/18
\n" ); document.write( "focus: (0,0-p)=(0,-7/18)
\n" ); document.write( "directrix: y=7/18
\n" ); document.write( "focal diameter also known as focal width=4p=14/9
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