document.write( "Question 588205: A takes 1 hour longer than B to walk 30km, A's pace was doubled,then A would take 2 hours less than B. find their rates of walking. pls. help me to solve this problem it's getting on my nerves....
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #374523 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
A takes 1 hour longer than B to walk 30km,
\n" ); document.write( " A's pace was doubled, then A would take 2 hours less than B.
\n" ); document.write( "find their rates of walking.
\n" ); document.write( ":
\n" ); document.write( "let a = A's walking pace (km/hr)
\n" ); document.write( "let b = B's walking pace
\n" ); document.write( ":
\n" ); document.write( "Write a time equation for their normal pace; Time = dist/speed
\n" ); document.write( "A's time - B's time = 1 hr
\n" ); document.write( "\"30%2Fa\" - \"30%2Fb\" = 1
\n" ); document.write( ":
\n" ); document.write( "Write a time equation when A has doubled his pace
\n" ); document.write( "B's time - A's time = 2 hrs
\n" ); document.write( "\"30%2Fb\" - \"30%2F%282a%29\" = 2
\n" ); document.write( "Reduce the fraction
\n" ); document.write( "\"30%2Fb\" - \"15%2Fa\" = 2
\n" ); document.write( ":
\n" ); document.write( "Arrange these two equations to use elimination here
\n" ); document.write( "\"30%2Fa\" - \"30%2Fb\" = 1
\n" ); document.write( "\"-15%2F%28a%29\" + \"30%2Fb\" = 2
\n" ); document.write( "-----------------------Addition eliminates b, find a
\n" ); document.write( "\"15%2Fa\" = 3
\n" ); document.write( "15 = 3a
\n" ); document.write( "a = 15/3
\n" ); document.write( "a = 5 km/hr, A's original speed
\n" ); document.write( ";
\n" ); document.write( "Find b using the 1st original equation
\n" ); document.write( "\"30%2F5\" - \"30%2Fb\" = 1
\n" ); document.write( "6 - \"30%2Fb\" = 1
\n" ); document.write( " -\"30%2Fb\" = 1 - 6
\n" ); document.write( " -\"30%2Fb\" = -5
\n" ); document.write( "30 = 5b
\n" ); document.write( "b = 30/5
\n" ); document.write( "b = 6 km/hr is B's original speed
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check this when A doubles his speed (10 km/hr)
\n" ); document.write( "\"30%2F6\" - \"30%2F10\" =
\n" ); document.write( "5 - 3 = 2 hrs
\n" ); document.write( ":
\n" ); document.write( "Hopefully we have restored your nerves to an agreeable level. C
\n" ); document.write( "
\n" );