document.write( "Question 588205: A takes 1 hour longer than B to walk 30km, A's pace was doubled,then A would take 2 hours less than B. find their rates of walking. pls. help me to solve this problem it's getting on my nerves....
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Algebra.Com's Answer #374523 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! A takes 1 hour longer than B to walk 30km, \n" ); document.write( " A's pace was doubled, then A would take 2 hours less than B. \n" ); document.write( "find their rates of walking. \n" ); document.write( ": \n" ); document.write( "let a = A's walking pace (km/hr) \n" ); document.write( "let b = B's walking pace \n" ); document.write( ": \n" ); document.write( "Write a time equation for their normal pace; Time = dist/speed \n" ); document.write( "A's time - B's time = 1 hr \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Write a time equation when A has doubled his pace \n" ); document.write( "B's time - A's time = 2 hrs \n" ); document.write( " \n" ); document.write( "Reduce the fraction \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Arrange these two equations to use elimination here \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "-----------------------Addition eliminates b, find a \n" ); document.write( " \n" ); document.write( "15 = 3a \n" ); document.write( "a = 15/3 \n" ); document.write( "a = 5 km/hr, A's original speed \n" ); document.write( "; \n" ); document.write( "Find b using the 1st original equation \n" ); document.write( " \n" ); document.write( "6 - \n" ); document.write( " - \n" ); document.write( " - \n" ); document.write( "30 = 5b \n" ); document.write( "b = 30/5 \n" ); document.write( "b = 6 km/hr is B's original speed \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this when A doubles his speed (10 km/hr) \n" ); document.write( " \n" ); document.write( "5 - 3 = 2 hrs \n" ); document.write( ": \n" ); document.write( "Hopefully we have restored your nerves to an agreeable level. C \n" ); document.write( " |