document.write( "Question 588428: The primeter of a rectangle is 30 cm,
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document.write( "Find the whole-number dimensions of the rectangle with:
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document.write( "(a) the greatest area
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document.write( "(b) the least area \n" );
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Algebra.Com's Answer #374497 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If you are allowed to use the fact that the largest area rectangle for a given perimeter is a square with side measure of the perimeter divided by 4, then divide 30 by 4 to get 7.5 and then round up to 8.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If you are required to prove that the largest area is a square then write back and I'll show you a proof.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The smallest would be a 0 by 15 rectangle with an area of zero, but a rectangle with a zero dimension is not a rectangle, it is a line. The restriction to stick with whole numbers means the two short sides must measure 1, leaving 14 for the two long sides. 1 times 14 is 14.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |