document.write( "Question 588419: find the area of a circle with a circumference of 1/2 inches
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Algebra.Com's Answer #374493 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
The formula for circumference is \"C+=+2pi%2Ar\". Use this with C = 1/2 to solve for r:\r
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\n" ); document.write( "\n" ); document.write( "\"C+=+2pi%2Ar\"\r
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\n" ); document.write( "\n" ); document.write( "\"1%2F2+=+2pi%2Ar\"\r
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\n" ); document.write( "\n" ); document.write( "\"1%2F4+=+pi%2Ar\"\r
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\n" ); document.write( "\n" ); document.write( "\"1%2F%284pi%29+=+r\"\r
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\n" ); document.write( "\n" ); document.write( "\"r+=+1%2F%284pi%29\"\r
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\n" ); document.write( "The area of a circle is \"A+=+pi%2Ar%5E2\". Plug in \"r+=+1%2F%284pi%29\" to find the area:\r
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\n" ); document.write( "\n" ); document.write( "\"A+=+pi%2Ar%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"A+=+pi%2A%281%2F%284pi%29%29%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"A+=+pi%2A%281%2F%2816pi%5E2%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"A+=+pi%2F%2816pi%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"A+=+1%2F%2816pi%29\"\r
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\n" ); document.write( "\n" ); document.write( "So the exact area of the circle is \"A+=+1%2F%2816pi%29\" square inches. \r
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\n" ); document.write( "\n" ); document.write( "If you use 3.14 for \"pi\", then the approximate area is 0.019894 square inches.\r
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\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r
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