document.write( "Question 588373: How do I reduce 21* 24/35 in lowest terms? \n" ); document.write( "
Algebra.Com's Answer #374473 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! 21* 24/35\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "504/35\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "72/5 ... Note: I divided both numerator and denominator by the GCF 7 to reduce.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So 21* 24/35 = 72/5\r \n" ); document.write( "\n" ); document.write( "-------------------------------------------------------------------------------------------------------------- \n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Jim \n" ); document.write( "-------------------------------------------------------------------------------------------------------------- \n" ); document.write( " |