document.write( "Question 587588: I need your help to solve 3(2a-1)<4(2a-3)and express the solution in interval notation \n" ); document.write( "
Algebra.Com's Answer #374461 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"3%282a-1%29%3C4%282a-3%29\" Start with the given inequality.\r
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\n" ); document.write( "\n" ); document.write( "\"6a-3%3C8a-12\" Distribute.\r
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\n" ); document.write( "\n" ); document.write( "\"6a%3C8a-12%2B3\" Add \"3\" to both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"6a-8a%3C-12%2B3\" Subtract \"8a\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"-2a%3C-12%2B3\" Combine like terms on the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"-2a%3C-9\" Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( "\"a%3E%28-9%29%2F%28-2%29\" Divide both sides by \"-2\" to isolate \"a\". note: Remember, the inequality sign flips when we divide both sides by a negative number. \r
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\n" ); document.write( "\n" ); document.write( "\"a%3E9%2F2\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solution is \"a%3E9%2F2\" \r
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\n" ); document.write( "\n" ); document.write( "The answer in interval notation is \r
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\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r
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