document.write( "Question 588217: I have tried to do this question a a lot of time but My answer and the Graph is not coming the Right way... so please help me.
\n" ); document.write( "this is the Question:
\n" ); document.write( "Concavity of the parabola representing the quadratic function, its y intercept and x intercepts if any exist, and the coordinates of the vertex. sketch the parabola
\n" ); document.write( "f(x)=2x^2+4.
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Algebra.Com's Answer #374455 by ankor@dixie-net.com(22740)\"\" \"About 
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Concavity of the parabola representing the quadratic function, its y intercept and x intercepts if any exist, and the coordinates of the vertex. sketch the parabola
\n" ); document.write( "f(x) = 2x^2 + 4
\n" ); document.write( "y = 2x^2 + 4
\n" ); document.write( "the y intercept is easy, when x = 0, y = 4 is the y intercept
\n" ); document.write( "Find the x intercept, (when y = 0)
\n" ); document.write( "2x^2 + 4 = 0
\n" ); document.write( "2x^2 = -4
\n" ); document.write( "x^2 = -4/2
\n" ); document.write( "x^2 = -2
\n" ); document.write( "x = \"sqrt%28-2%29\"
\n" ); document.write( "square root of a negative, no real roots, no x intercept
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\n" ); document.write( "The vertex occurs at the axis of symmetry, equation has no middle term, b=0
\n" ); document.write( "therefore the axis of symmetry is 0, hence the vertex, 0, 4
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\n" ); document.write( "If can you plot this equation, it is easy to see
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\n" ); document.write( " x | y
\n" ); document.write( "------- 2x^2 + 4 = y; substitute for x, find y
\n" ); document.write( "-2 | 12; 2(-2^2) + 4 = 2(4) + 4 = 12
\n" ); document.write( "-1 | 6: 2(-1^2) + 4 = 2(1) + 4 = 6
\n" ); document.write( " 0 | 4; 2(0) + 4 = 4
\n" ); document.write( "+1 | 6
\n" ); document.write( "+2 |12
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\n" ); document.write( "\n" ); document.write( "\"+graph%28+300%2C+200%2C+-4%2C+4%2C+-2%2C+10%2C+2x%5E2%2B4%29+\"
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