document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=588325>Question 588325</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help ASAP with my algebra question. We are on quadratic equations and I am stuck on a word problem: <BR>\n" );
document.write( "The area of a square can be doubled by increasing the length by 6 inches and the width by 4 inches. What is the length of the side of the square? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #374453 by </B><A HREF=/tutors/aboutme.mpl?userid=dfrazzetto><B>dfrazzetto(283)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dfrazzetto><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=dfrazzetto><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=374453\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "square to L=W\r<BR>\n" );
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document.write( "original area = LxL = L^2\r<BR>\n" );
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document.write( "(L+6)(L+4) = 2l^2\r<BR>\n" );
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document.write( "L^2 + 10L + 24 = 2L^2\r<BR>\n" );
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document.write( "L^2 - 10L - 24 = 0\r<BR>\n" );
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document.write( "(L-12)(L+2) = 0\r<BR>\n" );
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document.write( "L = 12, -2\r<BR>\n" );
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document.write( "12 inches </SPAN>\n" );
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