document.write( "Question 588315: what is the point-slope form of the linear equation whose graph passes through (-1,3) and (3,-9) \n" ); document.write( "
Algebra.Com's Answer #374446 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
First let's find the slope of the line through the points and \r
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\n" ); document.write( "\n" ); document.write( "Note: is the first point . So this means that \"x%5B1%5D=-1\" and \"y%5B1%5D=3\".\r
\n" ); document.write( "\n" ); document.write( "Also, is the second point . So this means that \"x%5B2%5D=3\" and \"y%5B2%5D=-9\".\r
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\n" ); document.write( "\n" ); document.write( "\"m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29\" Start with the slope formula.\r
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\n" ); document.write( "\n" ); document.write( "\"m=%28-9-3%29%2F%283--1%29\" Plug in \"y%5B2%5D=-9\", \"y%5B1%5D=3\", \"x%5B2%5D=3\", and \"x%5B1%5D=-1\"\r
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\n" ); document.write( "\n" ); document.write( "\"m=%28-12%29%2F%283--1%29\" Subtract \"3\" from \"-9\" to get \"-12\"\r
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\n" ); document.write( "\n" ); document.write( "\"m=%28-12%29%2F%284%29\" Subtract \"-1\" from \"3\" to get \"4\"\r
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\n" ); document.write( "\n" ); document.write( "\"m=-3\" Reduce\r
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\n" ); document.write( "\n" ); document.write( "So the slope of the line that goes through the points and is \"m=-3\"\r
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\n" ); document.write( "\n" ); document.write( "Now let's use the point slope formula:\r
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\n" ); document.write( "\n" ); document.write( "\"y-y%5B1%5D=m%28x-x%5B1%5D%29\" Start with the point slope formula\r
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\n" ); document.write( "\n" ); document.write( "\"y-3=-3%28x--1%29\" Plug in \"m=-3\", \"x%5B1%5D=-1\", and \"y%5B1%5D=3\"\r
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\n" ); document.write( "\n" ); document.write( "\"y-3=-3%28x%2B1%29\" Rewrite \"x--1\" as \"x%2B1\"\r
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\n" ); document.write( "\n" ); document.write( "So the answer is \"y-3=-3%28x%2B1%29\"\r
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