document.write( "Question 588184: A garden has a shape of an isosceles right triangle. The length of the hypotenuse is 24 feet. What is the Area of the garden? \n" ); document.write( "
Algebra.Com's Answer #374415 by mananth(16946)\"\" \"About 
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Pythagoras theorem\r
\n" ); document.write( "\n" ); document.write( "leg1^2+leg2^2= hypotenuse ^2\r
\n" ); document.write( "\n" ); document.write( "let the legs be x each\r
\n" ); document.write( "\n" ); document.write( "x^2+x^2= 24^2\r
\n" ); document.write( "\n" ); document.write( "2x^2= 24^2
\n" ); document.write( "x^2= 24 *24/2\r
\n" ); document.write( "\n" ); document.write( "x^2= 24*12
\n" ); document.write( "x^2= 288\r
\n" ); document.write( "\n" ); document.write( "Area of right triangle = 1/2 leg^2\r
\n" ); document.write( "\n" ); document.write( "=1/2 *288
\n" ); document.write( "= 144 sq. ft
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