document.write( "Question 588210: what is the formula for the following question please:
\n" ); document.write( "going to the beach 5km away,Jill rides her bike at 12 km/hr,Jack jogs at 8 km/hr,how much of a head start would Jill have to give Jack to reach the beach at the same time?
\n" ); document.write( "thank you.
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Algebra.Com's Answer #374411 by mananth(16946)\"\" \"About 
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cycling speed = 12 km/h
\n" ); document.write( "jogging speed = 8km/h\r
\n" ); document.write( "\n" ); document.write( "distance = 5 km\r
\n" ); document.write( "\n" ); document.write( "difference in time taken =\r
\n" ); document.write( "\n" ); document.write( "5/8 - 5/12\r
\n" ); document.write( "\n" ); document.write( "LCD =24
\n" ); document.write( "(15-10)/24 = 3/24 = 1/8 hours more\r
\n" ); document.write( "\n" ); document.write( "In 1/8 hours he will jog 1/8 * 8 = 1 km\r
\n" ); document.write( "\n" ); document.write( "Head start = 1km
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