document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=588203>Question 588203</A>: <I><SPAN STYLE=\"word-break: break-all;\"> log(x-6)- log (x-2) = log 5/x<BR>\n" );
document.write( "this is how I attempted to solve the problem<BR>\n" );
document.write( "(x-6) - (x-2) = log 5 - log x<BR>\n" );
document.write( "x-6-x+2 = 5 - x<BR>\n" );
document.write( "-6+2-5 = -y<BR>\n" );
document.write( "-9=-x<BR>\n" );
document.write( "9=x\r<BR>\n" );
document.write( "\n" );
document.write( "I came up with x=9, but my answer key says the answer is 10.  Will you please show me how to do this problem? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #374405 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=374405\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> log(x-6)- log (x-2) = log 5/x<BR>\n" );
document.write( "log(x-6)- log (x-2) - log 5/x=0<BR>\n" );
document.write( "log(x-6)- (log (x-2) + log 5/x)=0<BR>\n" );
document.write( "place under single log<BR>\n" );
document.write( "log[(x-6)/(x-2)*5/x]=0<BR>\n" );
document.write( "convert to exponential form: base(10) raised to log of number(0)=number[(x-6)/(x-2)*5/x]<BR>\n" );
document.write( "10^0=[(x-6)/(x-2)*5/x]=1<BR>\n" );
document.write( "x-6=(x-2)*5/x=(5x-10)/x<BR>\n" );
document.write( "x^2-6x=5x-10<BR>\n" );
document.write( "x^2-11x+10=0<BR>\n" );
document.write( "(x-10)(x-1)=0<BR>\n" );
document.write( "x=1 (reject, (x-2)>0)<BR>\n" );
document.write( "or <BR>\n" );
document.write( "x=10<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );